March 18th, 2019 
adminThis is a fairly straightforward problem all you need to know is that
##[H_3^+O] = 10^(-pH)##
Plugging in the value will produce
##[H_3^+O] = 10^(-8.85) = 0.00000000141 = 1.4 * 10^(-9) M##
SInce the pH is greater than 7 you are dealing with a basic solution
##pOH = 14 – pH = 14-8.85 = 5.15##
This means the concentration of ##OH^-## is
##[OH^-] = 10^(-pOH) = 10 ^-5.51 = 7.1 * 10^-6 M##
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