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You can find a procedure for at .
For HO O must be the central atom
The skeleton structure is H-O-H.
O has 6 valence electrons and each H has one.
You must arrange 8 electrons in pairs so that O has 8 and each H has two electrons in its valence shell.
The trial structure is
You have eight in your trial structure so it has the correct number of electrons.
The trial structure has the correct number of electrons.
The formal charge on each atom is:
H = 1 – (2) = 0; O = 6 4 – (4) = 0
The Lewis structure of HO is